a) Find the population after the second year.
First year - 100 / 10 = 10 = 10%
-100 + 10 = 110
Second year - 110 / 10 = 11 x 2 = 22 = 20%
-110 + 122 = 132
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The increase was not by 30% because the 20% was worked in after the 10 percent was already placed, making it 132.
11. A student is awarded a $1000 scholarship and places it in an account that pays 3% simple interest per year.
a) What is the total value of the scholarship amount at the end of the second year?
First Year - 1000 / 10 = 100 / 10 = 10 x 3 =30 = 3 %
-1000 + 30 = $1030
Second year - 1030 / 10 = 103 / 10 = 10.30 x 3 =30.90 = 3 %
- 1030 + 30.90 = $1060.90
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b) What is the single percent increase in value of the scholarship after two years?
(3 % = 30) + (3 % = 30.90) = 60.90 / 10 = 6.09% after two years
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