Deniel's scribpost 8-16 January 6th 2010 Question 16#

QUESTION 16#

Hey guys okay I really don't know if I was to do this question or not today but ill do it anyway...

The question I chose was Question 16 and it was the hard question but i figured it out anyway so here is my solution:

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What is the length of the red diagonal in the box? Express your answer to the nearest tenth of a millimetre.

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Here is my answer to this problem:

(Sorry if i didn't add any the letters a,b,c because it was hard putting them on the picture.)

When I was estimating I tried to figure out the problem by seeing what the question meant so here's what I did:

I multiplied the numbers by 2 making it 218 so I squared that number making it 14.8 because I rounded it by a tenth which makes this my solution but my answer is gonna be next.

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All I did was:

A²+B²+C² = ???

5mm² + 7mm² + 12mm² =???

So I multiplied them making an answer: (5x5)+(7x7)+(12x12)=218

So I squared the number making an answer which was: √218 = 14.7 rounding it making it 14.8

so that is my answer for Question 16#

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